engineering
beginner
10 sample questions
Control Systems MCQ Practice Test
Automation, feedback loops, and process control
Q1. A low-pass filter in a control system is primarily used to:
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A. Amplify the input signal
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B. Introduce a phase shift to the input signal
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C. Reduce the amplitude of high-frequency components of the input signal ✓
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D. Stabilize the output signal
Explanation: A low-pass filter allows low-frequency signals to pass through while attenuating high-frequency signals. This is achieved by reducing the amplitude of the high-frequency components.
Q2. In a type 1 PLL (Phase-Locked Loop), what is the transfer function of the loop filter?
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A. The transfer function of the loop filter is a PD controller (P + D/s).
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B. The transfer function of the loop filter is a PI controller (P + I/s). ✓
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C. The transfer function of the loop filter is a PID controller (P + I/s + D/s^2).
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D. The transfer function of the loop filter is a simple integrator (1/s).
Explanation: In a type 1 PLL, the loop filter is typically a PI controller, which provides a balance between the phase error and the integral of the phase error. This helps to stabilize the loop and achieve lock quickly.
Q3. A controller in a temperature control system uses a PID (Proportional-Integral-Derivative) algorithm to regulate the temperature. If the setpoint temperature is 20°C and the actual temperature is 22°C, the controller will initially respond with a control action that is proportional to the
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A. Temperature difference between setpoint and actual temperature. ✓
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B. Square of the temperature difference between setpoint and actual temperature.
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C. Inverse of the temperature difference between setpoint and actual temperature.
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D. Derivative of the temperature difference between setpoint and actual temperature.
Explanation: In a PID controller, the proportional term is directly proportional to the error between the setpoint and actual temperatures. This means that the controller will initially respond with a control action that is proportional to the temperature difference between the setpoint and actual temperatures.
Q4. A triangular membership function for "positive error" rises linearly from 0 at 0 V, reaches full membership (1.0) at 2 V, and falls linearly back to 0 at 4 V. What is the degree of membership for an error of 3 V?
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A. 0
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B. 0.25
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C. 0.5 ✓
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D. 1.0
Explanation: On the falling edge, membership = (4 - 3) / (4 - 2) = 1/2 = 0.5. The original stem omitted the support endpoints, making the membership value indeterminate, and the options were corrupted.
Q5. A DC motor is connected to a speed controller, and the speed is measured using a tachometer. The speed controller is set to maintain a constant speed of 1000 rpm, but the motor speed is oscillating between 980 and 1020 rpm. What is the likely cause of this oscillation?
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A. The motor is not properly aligned with the load.
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B. The speed controller is not tuned correctly. ✓
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C. The tachometer is not calibrated correctly.
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D. The motor is experiencing mechanical resonance.
Explanation: The speed controller is not tuned correctly, resulting in an unstable closed-loop system. This can cause the motor speed to oscillate around the setpoint.
Q6. A type-1 fuzzy logic controller is implemented in a control system to control the speed of a DC motor. The input to the fuzzy controller is the error between the desired speed and the actual speed, and the output is the duty cycle of the pulse-width modulation (PWM) signal. If the membership function of the error is triangular with a peak at 2 and a base width of 4, and the membership function of the output is triangular with a peak at 0.6 and a base width of 0.8, what is the type of defuzzification method used in this system?
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A. §The centroid method is used, which calculates the center of gravity of the area under the surface ✓
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B. §The mean of maximum method is used, which calculates the average of the output values that correspond to the maximum membership values
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C. §The weighted average method is used, which calculates the weighted average of the output values based on their membership grades
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D. §The height method is used, which calculates the average height of the surface above the x-axis
Explanation: In a type-1 fuzzy logic controller, the centroid method is a common defuzzification method used to calculate the crisp output value from the fuzzy output set. It calculates the center of gravity of the area under the surface, which represents the weighted average of the output values based on their membership grades.
Q7. In a PI controller, increasing the integral action (decreasing Ti) has what effect on steady-state error and overshoot?
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A. Steady-state error is eliminated faster, but overshoot may increase ✓
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B. Steady-state error increases
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C. It has no effect on steady-state error
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D. It eliminates overshoot entirely
Explanation: Stronger integral action drives the accumulated error to zero more quickly (removing offset) but adds phase lag, which typically increases overshoot and settling oscillation.
Q8. A type-1 Wind Turbine Generator (WTG) is modeled as a first-order system with a transfer function <img src=""/> G(s) = µ²² / (s + a). Given that the damping ratio (κ) is 0.5 and the natural frequency (φ_n) is 1 rad/s, determine the value of the damping coefficient (a) in the transfer function.
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A. a = 2φ_nκ ✓
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B. a = φ_n / κ
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C. a = φ_n * κ
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D. a = 2φ_n / κ
Explanation: The transfer function G(s) = µ²² / (s + a) represents a first-order system. The damping ratio (κ) and natural frequency (φ_n) are not directly applicable to a first-order system in the same way they are to a second-order system. However, the parameter 'a' in the denominator is related to the time constant of the system. In this case, the relationship between 'a', the damping ratio (κ, which is often implicitly 0.5 in this context, as the question states), and the natural frequency (φ_n) can be derived from the context of the question, which implies a second-order system behavior. For a second-order system, the standard form of the transfer function is G(s) = ω_n² / (s² + 2ζω_n s + ω_n²), where ζ is the damping ratio, and ω_n is the natural frequency. Comparing the given transfer function to the standard form, and considering the damping ratio and natural frequency, the correct relationship is a = 2 * κ * φ_n. Therefore, substituting the given values, a = 2 * 0.5 * 1 = 1.
Q9. A type 1 fuzzy logic controller is used to control the speed of an electric motor. The input membership function is a trapezoidal function with a core value of 30 and a support value of 20-50. What is the type of the fuzzy logic controller?
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A. Type 2 Fuzzy Logic Controller
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B. Type 1 Fuzzy Logic Controller with Trapezoidal Membership Function ✓
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C. Type 1 Fuzzy Logic Controller with Triangular Membership Function
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D. Type 2 Fuzzy Logic Controller with Gaussian Membership Function
Explanation: A type 1 fuzzy logic controller is a type of fuzzy logic controller that uses a single membership function to describe the input or output variables. In this case, the input membership function is a trapezoidal function, which is a specific type of membership function.
Q10. A PI (Proportional-Integral) controller is used to control a system with a transfer function given by G(s) = (s + 2)/(s(s + 5)). The PI controller is designed with a proportional gain of 2 and an integral time constant of 10 seconds. What is the closed-loop transfer function of the system?
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A. T(s) = (2s^2 + 4.2s + 0.4)/(s^3 + 7s^2 + 10s + 0.4)
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B. T(s) = (2s^2 + 4s + 0.4)/(s^3 + 7s^2 + 10s + 0.4) ✓
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C. T(s) = (2s^2 + 4s + 0.4)/(s^3 + 7s^2 + 10s + 4)
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D. T(s) = (2s^2 + 4.2s + 0.4)/(s^3 + 7s^2 + 10s + 4)
Explanation: The PI controller transfer function is Gc(s) = Kp + Ki/s, where Kp is the proportional gain and Ki is the integral gain. The integral time constant Ti is related to Ki by Ti = Kp/Ki. Therefore, Ki = Kp/Ti. In this case, Kp = 2 and Ti = 10, so Ki = 2/10 = 0.2. Thus, Gc(s) = 2 + 0.2/s = (2s + 0.2)/s. The plant transfer function is G(s) = (s + 2)/(s(s + 5)). The closed-loop transfer function T(s) is given by T(s) = (Gc(s) * G(s)) / (1 + Gc(s) * G(s)). Substituting the values, T(s) = ((2s + 0.2)/s * (s + 2)/(s(s + 5))) / (1 + (2s + 0.2)/s * (s + 2)/(s(s + 5))). Simplifying, T(s) = (2s^2 + 4s + 0.4) / (s^3 + 7s^2 + 10s + 0.4).
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